Godmode_Abuser, ( cos x + cos 2x + ... + (-1) ^ (n+1) * cos nx... ) Как я понимаю формула правильная нужна: Вот код: #include <iostream> #include <cmath> int main() { double x; std::cout << "x = "; std::cin >> x; int n; std::cout << "n = "; std::cin >> n; int sign = 1; double s = 0.0; for (int i = 1; i <= n; i++) { s += sign * cos(i * x); sign = -sign; } std::cout << "s = " << s; return 0; } C #include <iostream> #include <cmath> int main() { double x; std::cout << "x = "; std::cin >> x; int n; std::cout << "n = "; std::cin >> n; int sign = 1; double s = 0.0; for (int i = 1; i <= n; i++) { s += sign * cos(i * x); sign = -sign; } std::cout << "s = " << s; return 0; }