pocti_vladys, y=2x^3-2x/3-2x^2 при x=2 Формула u/v (2x^3-2x)'*(3-2x^2)-(2x^3-2x)*(3-2x^2)'/(3-2x^2)^2 (6x^2)*(3-2x^2)-(2x^3-2x)*(-4x)/(3-2x^2)^2 y'=(-4x^4+14x^2-6)/(3-2x^2)^2 x=2 y'=(-4*2^4+14*4-6)/(3-2*4)^2 y'=-14/25 The post was merged to previous Jun 2, 2021 pocti_vladys, 2. (uv)' -2x*(3x^3-5x)+(1-x^2)*(9x^2-5) y'=-15x+24x^2-5 The post was merged to previous Jun 2, 2021 pocti_vladys, 3.та же формула (u*v)'=u'v+uv', расписывать долго, у тебя время идёт, просто ответ y'=24x^2+16x-6 The post was merged to previous Jun 2, 2021 pocti_vladys, 4. y=x^2+1/1-x^2=u/v=u'v-uv'/v^2 y'=2x*(1-x^2)-(x^2+1)*(-2x)/(1-x^2)/ ^2 Ответ y'=4x/(1-x^2)^2 The post was merged to previous Jun 2, 2021 pocti_vladys, если что-то непонятно - спрашивай